# Jason Witherell # ETGG1801-01 # 8/25/2017 fname = "Jason" lname = "Witherell" number = 18.4 hours = 13 minutes = 53 radius = 8.5 cost = 16.75 cost_sq_in = cost / (3.1416 * radius ** 2) print(fname, lname) print(fname, lname, sep=":") print("The cube root of", number, "is", number ** (1/3)) print("There are", ((hours * 60) + minutes) * 60, "seconds in", hours, "hours and", minutes, "minutes.") print("The cost per square inch of a ", radius * 2, "-inch diameter $", cost, " pizza is $", cost_sq_in, sep="")