# Jason Witherell
# ETGG1801-01
# 8/25/2017

fname = "Jason"
lname = "Witherell"
number = 18.4
hours = 13
minutes = 53
radius = 8.5
cost = 16.75
cost_sq_in = cost / (3.1416 * radius ** 2)

print(fname, lname)
print(fname, lname, sep=":")
print("The cube root of", number, "is", number ** (1/3))
print("There are", ((hours * 60) + minutes) * 60, "seconds in", hours, "hours and", minutes, "minutes.")
print("The cost per square inch of a ", radius * 2, "-inch diameter $", cost, " pizza is $", cost_sq_in, sep="")